The probability that an employee is late for work on any given day is 0.27. What is the probability that the employee will be late on exactly 4 days out of 10 days?
Round your answer for two decimal places.
The probability that an employee is late for work on any given day is 0.27.
We have to find the probability that the employee would be late on exactly 4 days out of 10 days.
Now, if X be the number of days on which she is late, out of these 10 days, then X follows binomial distribution with parameters n=10, and p=0.27.
So, the PMF of X is
Now, we have to find
So, the required probability, rounded off to 2 decimal places is 0.17.
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