n=10,= 0.36, p=.44, α=.05, H0: p = .44, H1: p ≠ .44.
This is two tailed test.
Test Stat :
=0.44
Determine z-score _-0.5271
p-value = 2P( Z > |Test stat|)
=2P( Z > 0.53)
= 2 * [1 - P(Z < 0.53)]
=2 * (1 - 0.7019) ..................using normal distribution probability tables
Determine p= 0.59611
Since p-value > 0.05
fail to reject H0 at 5%.
There is insufficient evidence to conclude that true proportion is not 0.44.
Get Answers For Free
Most questions answered within 1 hours.