Question

18. A sample of 20 cans of tomato juice showed a standard deviation of 0.4 ounces....

18. A sample of 20 cans of tomato juice showed a standard deviation of 0.4 ounces. A 95% confidence interval estimate for the variance of the population is

a. 0.2313 to 0.8533

b. 0.2224 to 0.7924

c. 0.0889 to 0.3169

d. 0.0925 to 0.3413

Homework Answers

Answer #1

Solution :

Given that,

s = 0.4

Point estimate = s2 = 0.16

2R = 2/2,df = 32.852

2L = 21 - /2,df = 8.907

The 95% confidence interval for 2 is,

(n - 1)s2 / 2/2 < 2 < (n - 1)s2 / 21 - /2

(19)(0.16) / 32.852 < 2 < (19)(0.16) / 8.907

0.0925 < 2 < 0.3413  

(0.0925 to 0.3413)

option d. is correct

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The contents of a sample of 26 cans of apple juice showed a standard deviation of...
The contents of a sample of 26 cans of apple juice showed a standard deviation of 0.06 ounces. We are interested in testing to determine whether the variance of the population is significantly more than 0.003. At alpha of 0.10, we should Group of answer choices conclude that the variance of population is greater than 0.003 with a probability of 0.90 not reject the null hypothesis since the P-value is bigger than alpha. The population variance is not greater than...
A sample of 20 items provides a sample standard deviation of 5.                                
A sample of 20 items provides a sample standard deviation of 5.                                                                                      a. Compute the 90% confidence interval estimate of the population variance.                                                                                        b. Compute the 95% confidence interval estimate of the population variance.                                                                         c. Compute the 95% confidence interval estimate of the population variance.
A sample of 22 items provides a sample standard deviation of 6. (a) Compute the 90%...
A sample of 22 items provides a sample standard deviation of 6. (a) Compute the 90% confidence interval estimate of the population variance. (Round your answers to two decimal places.) ________ to _________ (b) Compute the 95% confidence interval estimate of the population variance. (Round your answers to two decimal places.) ________ to _______ (c) Compute the 95% confidence interval estimate of the population standard deviation. (Round your answers to one decimal place.) ________ to _________
A random sample of 51 charge sales showed a sample standard deviation of $47. A 90%...
A random sample of 51 charge sales showed a sample standard deviation of $47. A 90% confidence interval estimate of the population standard deviation is (Round your answers to 2 decimal places.)
A study regarding those that drink coffee showed that in a random sample of 18 individuals,...
A study regarding those that drink coffee showed that in a random sample of 18 individuals, the standard deviation for the number of times an individual drank coffee during a week was 5.2. Find the 95% confidence interval of the variance and the standard deviation. Show your work to receive credit
The contents of 3737 cans of Coke have a mean of x¯¯¯=12.1x¯=12.1 ounces and a standard...
The contents of 3737 cans of Coke have a mean of x¯¯¯=12.1x¯=12.1 ounces and a standard deviation of 0.130.13 ounces. Assume the contents of cans of Coke have an approximately normal distribution. Find the value of the test statistic tt for the claim that the population mean is μ=12. A random sample of 32 individuals was selected from the population of interest. The sample provided a mean of 19.5 and a standard deviation of 2.4. Find the p - value...
A certain brand of apple juice is supposed to have 64 ounces of juice. The filling...
A certain brand of apple juice is supposed to have 64 ounces of juice. The filling machine is not precise, and the exact amount of juice varies from bottle to bottle. Because the penalty for under filling is severe, the quality control manager wishes to verify the mean amount of juice in each bottle. She takes a random sample of 25 bottles, finding a mean of 63.6 ounces and a standard deviation of 0.8 ounces. The data from the 25...
QUESTION 4 From a population of cans of coffee marked "12 ounces," a sample of 25...
QUESTION 4 From a population of cans of coffee marked "12 ounces," a sample of 25 cans is selected and the contents of each can are weighed. The sample revealed a mean of 11.70 ounces and a sample standard deviation of 0.7 ounces. Test to see if the mean of the population is at least 12 ounces. (Assume the population is normally distributed.) Use a .05 level of significance.
The annual earnings of 14 randomly selected computer software engineers have a sample standard deviation of...
The annual earnings of 14 randomly selected computer software engineers have a sample standard deviation of $3668. Assume the sample is from a normally distributed population. Construct a confidence interval for the population variance sigma squared σ2 and the population standard deviation σ. Use a 95% level of confidence. Interpret the results. 1. What is the confidence interval for the population variance σ2​? (____,___) 2. Interpret the results. Select the correct choice below and fill in the answer​ box(es) to...
A study of 50 white mice showed that their average weight was 4.2 ounces. The standard...
A study of 50 white mice showed that their average weight was 4.2 ounces. The standard deviation of the population is 0.7 ounces. Which of the following is the 90% confidence interval for the mean weight per white mouse?
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT