Question

The results of the study showed that heterosexual woman, during ovulation, were significantly better at correctly identifying the marriage status of a man from a photograph of his face than women who were not ovulating. Near ovulation, on average want to correctly identified the marriage status about 66% of that 100 mannish onto them. Assume that the sample distribution for the study is unit in model and symmetric and that the samples are collected when if this is the probability of correctly identifying the marriage status of a man in any given photograph, what is the probability of a woman would correctly classify 78 or more of the men?

Answer 1

We have given here p=0.66 , n =100

np=0.66*100=66>10

n(1-p)=100*(1-0.66)=34>10

Therefore, We need to use here normal approximation to binomial.

The probability of a woman would correctly classify 78 or more of the men

.........................using continuity correction.

=P[Z>2.43]

=1-0.9925.......................using normal probability table.

=0.0075

Therefore,  the probability of a woman would correctly classify 78 or more of the men is 0.0075