Two-Sample T Tests for B by C
C N Mean SD SE
1 25 1309.2 344.28 68.857
2 25 1060.6 138.63 27.726
Difference 248.56 262.44 74.229
T-Tests for Mean Difference
Null Hypothesis: difference = 0
Alternative Hyp: difference ≠ 0
Lower Upper
Method Variances DF T P 95% C.I. 95% C.I.
Pooled Equal 48 3.35 0.0016 99.312 397.81
Satterthwaite Unequal 31.6 3.35 0.0021 97.282 399.84
Homogeneity of Variances DF F P
Folded F Test 24,24 6.17 0.0000
Cases Included 50 Missing Cases 0
(4 points)
Ho:
Ha:
Test Statistic: _____________ P-Value: _____________
Solution:
(a) To State the appropriate hypotheses that you wish to test to conduct a two-tailed test:
Null hypothesis H0: µ1 = µ2
Alternative hypothesis H1: µ1 ≠ µ2
(b) Suppose you were asked to really conduct a one-tailed test. Use the two-tailed printout above to find the test statistic and the p-value for the one-tailed test:
Test Statistic : 3.35
P- value = 0.0008
(c) 95% Confidence Interval for lower bound = 99.312
95% Confidence Interval for lower bound = 397.81
99.312 < µ1 - µ2 < 397.81
µ1 - µ2 < 0
µ1 < µ2
The population means of second brand is larger.
(d) To State all the assumptions that are necessary for this test to be valid:
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