Question

Two-Sample T Tests for B by C C           N          Mean       SD         SE 1   &nb

Two-Sample T Tests for B by C

C           N          Mean       SD         SE

1           25         1309.2   344.28   68.857

2           25         1060.6   138.63   27.726

Difference                      248.56   262.44   74.229

T-Tests for Mean Difference

Null Hypothesis: difference = 0

Alternative Hyp: difference ≠ 0

                                                                        Lower    Upper

Method Variances           DF          T             P       95% C.I. 95% C.I.

Pooled   Equal    48        3.35      0.0016   99.312 397.81

Satterthwaite       Unequal 31.6      3.35      0.0021   97.282 399.84

Homogeneity of Variances    DF         F              P

Folded F Test      24,24    6.17      0.0000

Cases Included 50    Missing Cases 0

  1. State the appropriate hypotheses that you wish to test to conduct a two-tailed test.

(4 points)

Ho:

Ha:

  1. Suppose you were asked to really conduct a one-tailed test. Use the two-tailed printout above to find the test statistic and the p-value for the one-tailed test. (4 points)

           Test Statistic: _____________         P-Value:         _____________

  1. Use the confidence interval on the printout to make an inference about which of the two populations means is larger. Make sure to state your measure of reliability. (4 points)
  1. State all the assumptions that are necessary for this test to be vali (5 points)

Homework Answers

Answer #1

Solution:

(a) To State the appropriate hypotheses that you wish to test to conduct a two-tailed test:

Null hypothesis H0: µ1 = µ2

Alternative hypothesis H1: µ1 ≠ µ2

(b) Suppose you were asked to really conduct a one-tailed test. Use the two-tailed printout above to find the test statistic and the p-value for the one-tailed test:

Test Statistic : 3.35

P- value = 0.0008

(c) 95% Confidence Interval for lower bound = 99.312

  95% Confidence Interval for lower bound = 397.81

99.312 < µ1 - µ2 < 397.81

µ1 - µ2 < 0

µ1 < µ2

The population means of second brand is larger.

(d) To State all the assumptions that are necessary for this test to be valid:

  • The data follows normal distribution.
  • The two samples are independent.
  • The data are continuous.
  • Both samples are simple random samples.
  • The variances of the two populations are equal.
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Create the printout for testing whether the mean closing price of all NYSE stocks differs from...
Create the printout for testing whether the mean closing price of all NYSE stocks differs from the mean closing price of all NASDAQ stocks and attach it here. Answer the following questions regarding this printout: Student Edition of Statistix 10.0                          4/21/2020, 5:32:15 AM Two-Sample T Tests for Close by Exchange Exchange           N         Mean       SD        SE 0                         40        51.664   73.709   11.654 1                         25        19.368   18.703   3.7406 Difference                    32.296   59.131   15.076 T-Tests for Mean Difference Null Hypothesis:...
Create the printout for testing whether the mean low stock price of all NYSE stocks differs...
Create the printout for testing whether the mean low stock price of all NYSE stocks differs from $35 and attach it here. Answer the following questions regarding this printout: One-Sample T Test Null Hypothesis: μ = 35 Alternative Hyp: μ ≠ 35                                                      Lower      Upper Variable     Mean       SE      T   DF        P   95% C.I.   95% C.I. Low        52.838   9.1892   1.94   39   0.0595     34.251     71.425 Cases Included 40    Missing Cases 0 In the words of the problem, give a practical conclusion for this test. Make sure to include your choice of α in this conclusion b. In the words...
Create the printout for testing whether the mean low stock price of all NYSE stocks differs...
Create the printout for testing whether the mean low stock price of all NYSE stocks differs from $35 and attach it here. Answer the following questions regarding this printout: Student Edition of Statistix 10.0                          4/20/2020, 6:48:59 PM One-Sample T Test Null Hypothesis: μ = 35 Alternative Hyp: μ ≠ 35                                                          Lower       Upper Variable     Mean       SE       T    DF        P    95% C.I.   95% C.I. Low        45.120   9.9629   1.02   39   0.3160     24.968     65.272 Cases Included 40    Missing Cases 0 In the words of the problem, give a practical conclusion for this test. Make sure to include your choice of α...
Create the printout for testing whether the mean current stock price of all NASDAQ stocks exceeds...
Create the printout for testing whether the mean current stock price of all NASDAQ stocks exceeds $22.00 and attach it here. Answer the following questions regarding this printout: One-Sample T Test Null Hypothesis: μ = 22 Alternative Hyp: μ ≠ 22                                                          Lower       Upper Variable     Mean       SE       T    DF        P    95% C.I.   95% C.I. Close      47.942   8.9817   2.89   64   0.0053     29.998     65.885 Cases Included 65    Missing Cases 0 State the assumption necessary for this printout to be valid. State the null and alternative hypotheses that we would use to determine if the mean current stock price of...
2. Create the printout for testing whether the mean current stock price of all NASDAQ stocks...
2. Create the printout for testing whether the mean current stock price of all NASDAQ stocks exceeds $22.00 and attach it here. Answer the following questions regarding this printout: Student Edition of Statistix 10.0                          4/21/2020, 5:30:26 AM One-Sample T Test Null Hypothesis: μ = 35 Alternative Hyp: μ ≠ 35                                                                                Lower    Upper Variable Mean       SE        T       DF             P      95% C.I. 95% C.I. Close    39.242   7.5372   0.56      64         0.5755   24.185...
Student Edition of Statistix 10.0     Apartment Data.xlsx, 5/25/2020, 9:09:26 PM One-Sample T Test Null Hypothesis: μ...
Student Edition of Statistix 10.0     Apartment Data.xlsx, 5/25/2020, 9:09:26 PM One-Sample T Test Null Hypothesis: μ = 750 Alternative Hyp: μ ≠ 750                                                          Lower       Upper Variable    Mean          SE          T DF         P      95% C.I.    95% C.I. Size 1405.6      60.156      10.90 74    0.0000      1285.7    1525.5 Cases Included 75    Missing Cases 0 State the null and alternative hypotheses that are being tested with the specified test. (3 points) Ho: Ha: Identify the...
Consider the computer output below. Two-Sample T-Test and CI Sample N Mean StDev SE Mean 1...
Consider the computer output below. Two-Sample T-Test and CI Sample N Mean StDev SE Mean 1 15 54.79 2.13 0.55 2 20 58.60 5.28 1.2 Difference = μ1-μ2 Estimate for difference: –3.91 95% upper bound for difference: ? T-test of difference = 0 (vs <): T-value = -2.93 P-value = ? DF = ? (a) Fill in the missing values. Use lower and upper bounds for the P-value. Suppose that the hypotheses are H0: μ1-μ2=0 versus H1: μ1-μ2<0. Enter your...
Independent Samples T-Test 95% CI for Mean Difference t df p Mean Difference SE Difference Lower...
Independent Samples T-Test 95% CI for Mean Difference t df p Mean Difference SE Difference Lower Upper Cohen's d Reading Level 1.995 69 0.003 0.878 0.289 0.293 1.493 0.721 The test is: Conduct a two-independent samples t test to determine if people with high IQs differ reading level compared to people without a high IQ. Using this table, first state if this test is directional or non directional. write the test results for a two-independent samples t-test. State which value...
The MINITAB printout shows a test for the difference in two population means. Two-Sample T-Test and...
The MINITAB printout shows a test for the difference in two population means. Two-Sample T-Test and CI: Sample 1, Sample 2 Two-sample T for Sample 1 vs Sample 2      N Mean StDev SE Mean Sample 1 5 29.00 3.00 1.3 Sample 2 7 28.89 3.63 1.4 Difference = mu (Sample 1) - mu (Sample 2) Estimate for difference: 0.11 95% CI for difference: (-4.3, 4.5) T-Test of difference = 0 (vs not =): T-Value = 0.06 P-Value = 0.96...
> x=c(5,3,1,6,4,3,2,4,7) > y=c(7,4,1,8,5,2,4,7,9) > mean(x) [1] 3.888889 > mean(y) [1] 5.222222 > sd(x) [1] 1.900292...
> x=c(5,3,1,6,4,3,2,4,7) > y=c(7,4,1,8,5,2,4,7,9) > mean(x) [1] 3.888889 > mean(y) [1] 5.222222 > sd(x) [1] 1.900292 > sd(y) [1] 2.728451 > t.test(x,y,var.equal=T)    Two Sample t-test data: x and y t = -1.203, df = 16, p-value = 0.2465 alternative hypothesis: true difference in means is not equal to 0 95 percent confidence interval: -3.682888 1.016221 sample estimates: mean of x mean of y 3.888889 5.222222 > t.test(x,y,var.equal=F)    Welch Two Sample t-test data: x and y t = -1.203,...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT