Question

Test the hypothesis using the​ P-value approach. Be sure to verify the requirements of the test. Upper H 0​: pequals0.9 versus Upper H 1​: pgreater than0.9 nequals200​; xequals185​, alphaequals0.1 Is np 0 left parenthesis 1 minus p 0 right parenthesisgreater than or equals​10? Yes No Use technology to find the​ P-value. ​P-valueequals nothing ​(Round to three decimal places as​ needed.) ▼ Do not reject Reject the null​ hypothesis, because the​ P-value is ▼ less greater than alpha.

Answer 1

Answer)

Given n = 200

P = 185/200

First we need to check the conditions of normality

That is if n*p and n*(1-p) both are greater than 5 or not

N*p = 185

And n*(1-p) = 15

As both the conditions are met

So, we can use standard normal z table to conduct the test.

Ho : p = 0.9

Ha : p > 0.9

Test statistics z = (observed p - claimed p)/standard error

Standard error = √{claimed p*(1-claimed p)}/√n

Observed p = 185/200

Claimed p = 0.9

N = 200

Test statistics z = 1.18

From z table, p(z>1.18) = 0.1190

P-value = 0.119

As the obtained p-value is greater than the given significance level 0.1

We fail to reject Ho