Assume a normal distribution and find the following
probabilities.
(Round the values of z to 2 decimal places. Round your
answers to 4 decimal places.)
P(x ≥ 73 | μ = 60 and σ = 2.82)
Solution :
Given that ,
mean = = 60
standard deviation = = 2.82
P(x 73) = 1 - P(x 73 )
= 1 - P[(x - ) / (73 - 60) / 2.82]
= 1 - P(z 4.61)
Using z table,
= 1 - 1
= 0
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