Question

# If your critical value is 1.7 then you are running a: left tailed test two tailed...

If your critical value is 1.7 then you are running a:

• left tailed test
• two tailed test
• unable to determine from this information
• right tailed test

If your critical value is 1.7 and the test statistic is 0.7 you would:

• fail to reject the Ho
• reject the Ho
• unable to determine from this information
• accept the Ho

If your critical value is 1.7 and the test statistic is 0.7 you would be:

• unable to show that the average is less than the claim
• able to show that the average was greater than the claim
• unable to show that the average was different than the claim
• able to show that the average is less than the claim
• unable to show that the average was greater than the claim

If your critical value is -2.3 then you are running a:

• unable to determine from this information
• right tailed test
• two tailed test
• left tailed test

If your critical value is -2.3 and the test statistic is -1.2 you would:

• fail to reject the Ho
• reject the Ho
• unable to determine from this information
• accept the Ho

If your critical value is -2.3 and the test statistic is -1.2 you would be:

• able to show that the average is less than the claim
• unable to show that the average is less than the claim
• unable to show that the average was greater than the claim
• able to show that the average was greater than the claim
• unable to show that the average was different than the claim

If your critical value is 1.7 then you are running a right tailed test

If your critical value is 1.7 and the test statistic is 0.7 you would fail to reject the H​​​​​​0

If your critical value is 1.7 and the test statistic is 0.7 you would be unable to show that the average was greater than the claim

If your critical value is -2.3 then you are running a left tailed test

If your critical value is -2.3 and the test statistic is -1.2 you would fail to reject the H​​​​​​0

If your critical value is -2.3 and the test statistic is -1.2 you would be unable to show that the average is less than the claim

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