A random sample of 100 observations from a quantitative population produced a sample mean of 30.8 and a sample standard deviation of 7.8. Use the p-value approach to determine whether the population mean is different from 32. Explain your conclusions. (Use α = 0.05.)
Find the test statistic and the p-value. (Round your test statistic to two decimal places and your p-value to four decimal places.)
z =
p-value =
Solution :
This is the two tailed test .
The null and alternative hypothesis is ,
H0 : = 32
Ha : 32
Test statistic(z)
= ( - ) / / n
= (30.8 - 32) / 7.8 / 100
Test statistic = -1.54
P(z < - 1.54) = 2 * P(z < -1.54) = 2 * 0.0618
P-value = 0.1236
= 0.05
P-value >
Fail to reject the null hypothesis .
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