Question

A group of 200 patients tested a new medication. Some tried the new medication, and the...

A group of

200

patients tested a new medication.
Some tried the new medication, and the rest took the old medication.

The results are reported in the following two-way frequency table.

No improvement Improvement
Old medication

79

29

New medication

23

69

A patient is chosen at random from this group.

Complete the following. Write your answers as decimals.

(a)Find the probability that the patient showed improvement.

=P(improvement)

(b)Find the probability that the patient showed improvement, given that he took the new medication.

=P(improvement | new medication)

(c)Is there evidence that a patient who takes the new medication is more likely to show improvement than a randomly chosen patient from the group?

Yes, because the probability found in part (b) is much greater than the probability found in part (a).

No, because the probability found in part (b) is much greater than the probability found in part (a).

Yes, because the probability found in part (a) is much greater than the probability found in part (b).

No, because the probability found in part (a) is much greater than the probability found in part (b).

Yes, because the probability found in part (b) is about the same as the probability found in part (a).

No, because the probability found in part (b) is about the same as the probability found in part (a).

Homework Answers

Answer #1

a) The probability that the patient showed improvement is computed here as:
= Total patients who show improvement / Total patient size

= (29 + 69)/200

= 0.49

Therefore 0.49 is the required probability here.

b) The probability that the patient showed improvement, given that he took the new medication is computed using Bayes theorem as:

P( improvement | new medication) = n(improvement and new medication)/ n(new medication)

= 69 / (69 + 23)

= 69/92

= 0.75

Therefore 0.75 is the required probability here.

c) Clearly given that the patient takes new medication, the probability of improvement as in part b) is greater than the probability of improvement in a randomly selected patient. Therefore Yes, because the probability found in part (b) is much greater than the probability found in part (a) is the correct answer here.

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