It is known that 12% of children are nearsighted. A random sample of 170 children is selected. What is the probability less than 14% of this sample will be nearsighted?
Solution :
Given that ,
p = 0.12
1 - p = 0.88
n = 170
= p = 0.12
= (p*(1-p))/n = (0.12*0.88)/170 = 0.02492
P( < 0.14) = P(( - ) / < (0.14 - 0.12) / 0.02492)
= P(z < 0.80)
= 0.7881
Probability = 0.7881
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