Random samples of four different models of cars were selected and the gas mileage of each car was measured. The results are shown below.
Model A / Model B / Model C / Model D 29 / 29 / 29 / 26 27 / 26 / 24 / 21 24 / 21 / 27 / 24 23 / 21 / 22 / 29
Test the claim that the four different models have the same population mean. Use a significance level of 0.05. Show all work please
A | B | C | D |
29 | 27 | 24 | 23 |
29 | 26 | 21 | 21 |
29 | 24 | 27 | 22 |
26 | 21 | 24 | 29 |
Using Excel, go to Data, select Data Analysis, choose Anova: Single Factor and group by columns.
SUMMARY | |||||||
Groups | Count | Sum | Average | Variance | |||
A | 4 | 113 | 28.25 | 2.25 | |||
B | 4 | 98 | 24.50 | 7.00 | |||
C | 4 | 96 | 24.00 | 6.00 | |||
D | 4 | 95 | 23.75 | 12.92 | |||
ANOVA | |||||||
Source of Variation | SS | df | MS | F | P-value | F crit | |
Between Groups | 53.25 | 3 | 17.75 | 2.52 | 0.11 | 3.49 | |
Within Groups | 84.5 | 12 | 7.04 | ||||
Total | 137.75 | 15 |
H0: μ1 = μ2 = μ3 = μ4
H1: At least one μi is different from others
p-value = 0.11
Since p-value is more than 0.05, we do not reject the null hypothesis and conclude that μ1 = μ2 = μ3 = μ4.
So, the four different models have the same population mean.
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