Question

Starting salaries of 64 college graduates who have taken a statistics course have a mean of $42,500 with a standard deviation of $6,800. Find a 68% confidence interval for ?μ. (NOTE: Do not use commas or dollar signs in your answers. Round each bound to three decimal places.)

Answer #1

Solution :

sample size = n = 64

Degrees of freedom = df = n - 1 = 63

t_{
/2,df} = 1.002

Margin of error = E = t_{/2,df}
* (s /n)

= 1.002 * (6800 / 64)

Margin of error = E = 851.7

The 68% confidence interval estimate of the population mean is,

- E < < + E

42500 - 851.7 < < 42500 + 851.7

41648.3 < < 43351.7

Confidence interval = 41648**.**300 to
43351**.**700

Starting salaries of 64 college graduates who have taken a
statistics course have a mean of $43,500 with a standard deviation
of $6,800. Find a 68% confidence interval for μ. (NOTE: Do not use
commas or dollar signs in your answers. Round each bound to three
decimal places.)
Lower-bound:
Upper-bound:

(1 point) Starting salaries of 135 college graduates who have
taken a statistics course have a mean of $42,583. The population
standard deviation is known to be $9,171. Using 99% confidence,
find both of the following:
A. The margin of error:
B. Confidence interval: ,

Salaries of 4747 college graduates who took a statistics course
in college have a mean, x overbarx, of $63,000. Assuming a
standard deviation, sigmaσ, of $16 comma 37216,372, construct
a
9090% confidence interval for estimating the population mean
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(Round to the nearest integer as needed.)

Salaries of 44 college graduates who took a statistics course in
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deviation,σ,of $12,063,construct a 95% confidence interval for
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____< mu<____

Salaries of 47 47 college graduates who took a statistics course
in college have a mean, x overbar x, of $ 63 comma 400 $63,400.
Assuming a standard deviation, sigma σ, of $ 11 comma 850
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Salaries of 45 college graduates who took a statistics course in
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Salaries of 48 college graduates who took a statistics course in
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deviation, sigma, of $10,499, construct a 90% confidence
interval for estimating the population mean mu. Click here to view
a t distribution table. LOADING... Click here to view page 1 of the
standard normal distribution table. LOADING... Click here to view
page 2 of the standard normal distribution table. LOADING... $
nothingless thanmuless than$ nothing (Round to the...

How to calculate margin of error for this question?
Starting salaries of 80 college graduates who have taken a
statistics course have a mean of $42,893. Suppose the distribution
of this population is approximately normal and has a standard
deviation of $10,748.
Use a 93% confidence level.
Can't get the answer right :(

Question 3 4 pts
A sample of salaries of 57 college graduates who took a
statistics course in college have a mean of $78,829 and a
standard deviation of $10,086. Construct a 91% confidence
interval for estimating the population mean.

Annual starting salaries for college graduates with degrees in business administration are generally expected to be between $10,000 and $35,000. Assume that a 95% confidence interval estimate of the population mean annual starting salary is desired. Given the information in the Microsoft Excel Online file below, construct a spreadsheet to determine how large a sample should be taken for each desired margin of error.
Annual starting salaries for college graduates with degrees in
business administration are generally expected to be...

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