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You measure 34 watermelons' weights, and find they have a mean weight of 44 ounces. Assume...

You measure 34 watermelons' weights, and find they have a mean weight of 44 ounces. Assume the population standard deviation is 5.3 ounces. Based on this, what is the maximal margin of error associated with a 99% confidence interval for the true population mean watermelon weight.

As in the reading, in your calculations:
--Use z = 1.645 for a 90% confidence interval
--Use z = 2 for a 95% confidence interval
--Use z = 2.576 for a 99% confidence interval.

Give your answer as a decimal, to two places

Math   Statistics-And-Probability   
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Solution: You measure 34 watermelons' weights, and find they have a mean weight of 44 ounces. Assume the population standard deviation is 5.3 ounces. Based on this, what is the maximal margin of error associated with a 99% confidence interval for the true population mean watermelon weight.

Answer: Maximal margin of error associated with a 99% confidence interval for the true population mean is:

Therefore 2.34 is the maximal margin of error associated with a 99% confidence interval for the true population mean.

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