A sample mean, sample size, and population standard deviation are provided below. Use the one-mean z-test to perform the required hypothesis test at the 55% significance level.
x=35, n=34, o=7, H0: u=37, Ha: u<37
Solution :
= 37
=35
=7
n = 34
This is the left tailed test .
The null and alternative hypothesis is
H0 : = 0.38
Ha : < 0.38
Test statistic = z = ( - ) / / n
= (35- 37) /7 / 34
= -1.666
P (Z <-1.666 ) =0.0479*2 = 0.0958
P-value = 0.0958
= 0.55
0.0958 < 0.55
Reject the null hypothesis .
There is sufficient evidence to suggest that
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