Unit sales for new product ABC have varied in the first seven months of this year as follows:
Month | Jan | Feb | Mar | Apr | May | Jun | Jul |
---|---|---|---|---|---|---|---|
Unit Sales | 145 | 492 | 319 | 265 | 389 | 321 | 180 |
What is the (population) standard deviation of the data?
Please round your answer to the nearest integer.
Note that the correct answer will be evaluated based on the full-precision result you would obtain using Excel.
Solution:
The formulas for mean, variance, and standard deviation for sample are given as below:
Population Mean = µ = ∑ X/n
Population Variance = σ2 = ∑[ (X - mean)^2]/n
Population Standard deviation = σ = Sqrt(S2) = Sqrt(Variance)
The calculation table is given as below:
Month |
X |
(X - mean)^2 |
1 |
145 |
24514.6033 |
2 |
492 |
36263.0517 |
3 |
319 |
303.756098 |
4 |
265 |
1337.467298 |
5 |
389 |
7643.760098 |
6 |
321 |
377.470498 |
7 |
180 |
14779.6053 |
Total |
2111 |
85219.71429 |
From above table, we have
n = 7
Population Mean = µ = 2111/7 = 301.5714
Population Variance = σ2 = 85219.71429/7 = 12174.2449
Population Standard deviation = σ = Sqrt(12174.2449) = 110.3369607
What is the (population) standard deviation of the data?
Answer: 110
(Rounded to nearest integer)
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