What is the minimum sample size needed to estimate the mean age of the books in a library to within 2 months with 95% confidence if the standard deviation of the ages is thought to be about 60 months?
Solution :
Given that,
standard deviation = = 60
margin of error = E = 2
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.960
Sample size = n = ((Z/2 * ) / E)2
= (1.960 * 60) / 2)2
=3457.44
= 3457
The minimum sample size = 3457
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