The interarrival time of customers for 60 min was monitored and reported below:
0.56974538 6.25245930 4.38116270 2.73018725 0.01947573 2.05621644
0.95476822 0.20938206 0.36555334 13.31611807 1.84342165 3.85799384
0.78148032 0.06480221 1.01586982 1.54638918 1.65045201 8.62226018
1.41718532 3.75108604
What is p-value of the KS test testing the hypothesis that the interarrival times are exponentially distributed?
Null Hypothesis: The interarrival times are exponentially distributed.
Alternative Hypothesis: The interarrival times are exponentially not distributed.
from the above table, we can conclude that the p-value 0.908 which is greater than 0.05. So, we have to accept the null Hypothesis i.e, the interarrival times are exponentially distributed.
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