Question

The interarrival time of customers for 60 min was monitored and reported below: 0.56974538 6.25245930 4.38116270...

The interarrival time of customers for 60 min was monitored and reported below:

0.56974538 6.25245930 4.38116270 2.73018725 0.01947573 2.05621644

0.95476822 0.20938206 0.36555334 13.31611807 1.84342165 3.85799384

0.78148032 0.06480221 1.01586982 1.54638918 1.65045201 8.62226018

1.41718532 3.75108604

What is p-value of the KS test testing the hypothesis that the interarrival times are exponentially distributed?

Homework Answers

Answer #1

Null Hypothesis: The interarrival times are exponentially distributed.

Alternative Hypothesis: The interarrival times are exponentially not distributed.

from the above table, we can conclude that the p-value 0.908 which is greater than 0.05. So, we have to accept the null Hypothesis i.e, the interarrival times are exponentially distributed.

  

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