Question

Assume that an adult female is randomly selected. Suppose females have pulse rates that are normally distributed with a mean of

71.071.0

beats per minute and a standard deviation of

12.512.5

beats per minute. Find the probability of a pulse rate between

5757

beats per minute and

6767

beats per minute.​ (Hint: Draw a​ graph.)

The probability is....

Answer 1

Solution :

Given that ,

mean = = 71.0

standard deviation = = 12.5

P(57 < x < 67) = P((57 - 71)/ 12.5) < (x - ) /  < (67 - 71) / 12.5) )

= P(-1.12 < z < -0.32)

= P(z < -0.32) - P(z < -1.12)

= 0.3745 - 0.1314 Using standard normal table,  

Probability = 0.2431