Create a 90% confidence interval about a sample proportion given that the sample proportion is .61 and the sample size is 1250.
Solution :
Given that,
n = 1250
Point estimate = sample proportion = = 0.61
1 - = 1 - 0.61 = 0.39
At 90% confidence level
= 1 - 90%
=1 - 0.90 =0.10
/2
= 0.05
Z/2
= Z0.05 = 1.645
Margin of error = E = Z / 2 * (( * (1 - )) / n)
= 1.645 (((0.61 * 0.39) / 1250 )
= 0.023
A 90% confidence interval for population proportion p is ,
± E
= 0.61 ± 0.023
= ( 0.587, 0.633 )
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