Question

The following is sample information. Test the hypothesis that the treatment means are equal. Use the 0.02 significance level.

Treatment 1	Treatment 2	Treatment 3
3	10	4
8	6	6
3	9	3
5	7	10

a. State the null hypothesis and the alternate hypothesis.

H₀:                (Click to select)  The treatment means are not all the same.  The treatment means are the same.

H₁:                (Click to select)  The treatment means are the same.  The treatment means are not all the same.

b. What is the decision rule? (Round the final answer to 2 decimal places.)

Reject H₀ if the test statistic is greater than                 .

c. Compute SST, SSE, and SS total. (Round the final answers to 3 decimal places.)

SST =                

SSE =                

SS total =                

d. Complete the ANOVA table. (Round the SS, MS, and F values to 3 decimal places.)

Source	SS	DF	MS	F
Treatment
Error
Total

e. State your decision regarding the null hypothesis.

(Click to select)  Reject  Do not reject  H₀.

Answer 1

a)

Ho: The treatment means are the same.

Ha: The treatment means are not all the same.

b)

Applying one way ANOVA: (use excel: data: data analysis: one way ANOVA: select Array):

Reject H₀ if the test statistic is greater than   6.23

c)

SST =22.167

SSE =55.500

SSTotal =77.667

d)

Source	SS	df	MS	F
treatment	22.167	2	11.083	1.797
error	55.500	9	6.167
Total	77.667	11

e)

since test statistic <critical value

Do not reject  H₀.