A parent believes that the average height for 14 year old girls differs from that of 14 year old boys. The summary data are listed below where height is in feet: the sample mean of 5.1 and the population standard deviation of 0.2 based on a random sample of size 40 from 14 year old girls. What are the point estimate and the margin of error with 95% confidence level?
Solution :
Given that,
Point estimate = = 5.1
= 0.2
n = 40
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96
Margin of error = E = Z/2* ( /n)
= 1.96 * (0.2 / 40)
= 0.062
Margin of error = E = 0.062
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