Consider a drug testing company that provides a test for marijuana usage. Among
287
tested subjects, results from
26
subjects were wrong (either a false positive or a false negative). Use a
0.10
significance level to test the claim that less than
10
percent of the test results are wrong.
Solution :
Given that ,
n = 287
x = 26
The null and alternative hypothesis is ,
H0 : p = 0.10
Ha : p < 0.10
This is the left tailed test .
= x / n = 26 / 287 = 0.0906
P0 = 10 % = 0.10
1 - P0 = 1-0.10 = 0.90
Test statistic = z
= - P0 / [P0 * (1 - P0 ) / n]
= 0.0906 - 0.10 / [0.10 ( 1 - 0.10) / 287 ]
= -0.531
The test statistic = -0.531
P-value = 02976.
= 0.10
0.2976 > 0.10
P-value >
Fail to reject the null hypothesis .
There is not sufficient evidence to test the claim .
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