A claim is made that the average salary for all jobs in Minnesota is less than $74,500. You are going to test the claim using α=0.05 and assume that your data is normally distributed and the population standard deviation (σ) is not known.
Here is the data I came up with in Excel for a Hypothesis test.
Calculations/Values | Formulas/Answers |
Mean (x-bar) | 72027.32418 |
Standard Deviation | 22728.49557 |
n | 364 |
mu | |
Test Statistic | -312.9194042 |
Critical Value | 1.644853627 |
P-value |
Salary | |
Mean | 72027.32418 |
Known Variance | 22728.49557 |
Observations | 364 |
Hypothesized Mean | 74500 |
z | -312.9194042 |
P(Z<=z) one-tail | |
z Critical one-tail | 1.644853627 |
I need help determining if I should reject the null hypothesis based on the critical value approach and if the p-value matches the conclusion based on that method.
critical value (-) for left tail (+) for right tail
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