Question

4 randomly selected cans of pumpkin pie mix contain a mean of 30 ounces / per can . Verify the claim that an average of pie mix in one can exceeds 31.5 ounces if the contents of the cans are normally distributed with a standard deviation 2 ounces.

How do I find the P-Value?

Answer 1

Solution:

This a right (One) tailed test.

The null and alternative hypothesis is,  

Ho: 31.5

Ha: 31.5

The test statistics,

t = ( - )/ (s/)

= ( 30 - 31.5 ) / ( 2 /4 )

= -1.5

df = n - 1 = 3

P-value = 0.8847