Question

Previous experience shows the standard deviation of a given process to be 3.7. A manufacturing engineer...

Previous experience shows the standard deviation of a given process to be 3.7. A manufacturing engineer is concerned that the standard deviation has changed. a) State the Hypothesis to show the standard deviation of the process has changed? b) To test the hypothesis, the manufacturing engineer takes a random sample of 12 from the process and records the variable of interest. The data appear in the Process worksheet of the Hypothesis Tests HW data workbook on Moodle. Use JMP to test the hypothesis of part a). c) Using  = 0.05, draw a conclusion for the hypothesis test. Make sure you state your conclusion in the context of the problem

Variable

52

44

51

58

48

49

38

49

50

42

55

51

Homework Answers

Answer #1

Claim: The standard deviation of the process has changed.

Sample size = n = 12

Sample standard deviation = s = 5.4848

a) The null and alternative hypothesis is

b) Test statistic is

Level of significance = 0.05

Degrees of freedom = n - 1 = 12 - 1 = 11

P-value = P( ) = 0.0120

c) Since P-value is less than the level of significance, We reject the null hypothesis. There sufficient evidence to conclude that the standard deviation of the process has changed.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Previous experience shows the variance of a given process to be 14. Researchers are testing to...
Previous experience shows the variance of a given process to be 14. Researchers are testing to determine whether this value has changed. They gather the following dozen measurements of the process. Use these data and α=0.05 to test the null hypothesis about the variance. Assume the measurements are normally distributed. 52 44 51 58 48 49 38 49 50 42 55 51
A digital camcorder repair service has set a goal not to exceed an average of 5...
A digital camcorder repair service has set a goal not to exceed an average of 5 working days from the time the unit is brought in to the time repairs are completed. a) State the Hypothesis to show the goal is being met. b) To test the hypothesis, the repair service takes a random sample of 12 repair records and recorded the repair time (in days). The data appear in the repair worksheet of the Hypothesis Tests HW data workbook...
Moen has instituted a new manufacturing process for assembling a component. Using the old process, the...
Moen has instituted a new manufacturing process for assembling a component. Using the old process, the average assembly time was 4.25 minutes per component. After the new process was in place for 30 days, the quality control engineer took a random sample of fourteen components and noted the time it took to assemble each component. Based on the sample data, the average assembly time was 4.38 minutes, with a standard deviation of .16 minutes. Using a significance level of .02,...
Mean 3407.94 Median 2364.00 Standard Deviation 3988.42 Minimum 136.00 Maximum 21451.00 n=52 Determine if there is...
Mean 3407.94 Median 2364.00 Standard Deviation 3988.42 Minimum 136.00 Maximum 21451.00 n=52 Determine if there is sufficient evidence to conclude the average amount of marriages is greater or equal to 7000 in the United States and territories at the .05 level of significance. Clearly state a null and alternative hypothesis Give the value of the test statistic Report the P-Value Clearly state your conclusion (Reject the Null or Fail to Reject the Null) Explain what your conclusion means in context...
summary for marriages Mean 3407.94 Median 2364.00 Standard Deviation 3988.42 Minimum 136.00 Maximum 21451.00 n=52 Determine...
summary for marriages Mean 3407.94 Median 2364.00 Standard Deviation 3988.42 Minimum 136.00 Maximum 21451.00 n=52 Determine if there is sufficient evidence to conclude the average amount of marriages is greater or equal to 9000 in the United States and territories at the .05 level of significance Clearly state a null and alternative hypothesis Give the value of the test statistic Report the P-Value Clearly state your conclusion (Reject the Null or Fail to Reject the Null) Explain what your conclusion...
Summary for Deaths Mean 3663.88 Median 2695.5 Standard Deviation 3656 Minimum 306 Maximum 17680 Simple size...
Summary for Deaths Mean 3663.88 Median 2695.5 Standard Deviation 3656 Minimum 306 Maximum 17680 Simple size 52 b.    Determine if there is sufficient evidence to conclude the average amount of deaths is equal to 6000 in   the United States and territories at the 0.10 level of significance. Clearly state a null and alternative hypothesis Give the value of the test statistic Report the P-Value Clearly state your conclusion (Reject the Null or Fail to Reject the Null) Explain what your...
Summary for Deaths Mean 3883.17 Median 2685.50 Standard Deviation 3908.65 Minimum 299.00 Maximum 19140.00 n=52 Determine...
Summary for Deaths Mean 3883.17 Median 2685.50 Standard Deviation 3908.65 Minimum 299.00 Maximum 19140.00 n=52 Determine if there is sufficient evidence to conclude the average amount of deaths is below is less than or equal to 6000 in the United States and territories at the 0.10 level of significance. Clearly state a null and alternative hypothesis Give the value of the test statistic Report the P-Value Clearly state your conclusion (Reject the Null or Fail to Reject the Null) Explain...
Summary for Deaths Mean 3883.17 Median 2685.50 Standard Deviation 3908.65 Minimum 299.00 Maximum 19140.00 n=52 Determine...
Summary for Deaths Mean 3883.17 Median 2685.50 Standard Deviation 3908.65 Minimum 299.00 Maximum 19140.00 n=52 Determine if there is sufficient evidence to conclude the average amount of deaths is below is less than or equal to 5500 in the United States and territories at the 0.10 level of significance. Clearly state a null and alternative hypothesis Give the value of the test statistic Report the P-Value Clearly state your conclusion (Reject the Null or Fail to Reject the Null) Explain...
births Mean: 359666.67 standard Deviation: 16864.88 n= 12 Determine if there is sufficient evidence to conclude...
births Mean: 359666.67 standard Deviation: 16864.88 n= 12 Determine if there is sufficient evidence to conclude the average amount of births is over 5000 in the United States and territories at the 0.05 level of significance. Clearly state a null and alternative hypothesis Give the value of the test statistic Report the P-Value Clearly state your conclusion (Reject the Null or Fail to Reject the Null) Explain what your conclusion means in context of the data.
**Please calculate using JMP and show anaylsis* When operating normally, a manufacturing process produces tablets for...
**Please calculate using JMP and show anaylsis* When operating normally, a manufacturing process produces tablets for which the mean weight of the active ingredient is 5 grams, and the standard deviation is 0.025 gram. For a random sample of 12 tables the following weights of active ingredient (in grams) were found: 5.01 4.69 5.03 4.98 4.98 4.95 5.00 5.00 5.03 5.01 5.04 4.95 Without assuming that the population variance is known, test the null hypothesis that the population mean weight...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT