Construct the 99% confidence interval estimate of the population proportion p if the sample size is n=700 and the number of successes in the sample is x=251.
____<p<____
Solution :
Given that,
Point estimate = sample proportion = = x / n = 251 / 700 = 0.359
Margin of error = E = Z / 2 * (( * (1 - )) / n)
= 2.576 * (((0.359 * 0.641) / 700)
Margin of error = E = 0.047
A 99% confidence interval for population proportion p is ,
0.359 - 0.047 < p < 0.359 + 0.047
0.312 < p < 0.406
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