Question

2. A random sample of 25 male runners has a mean of ̄x= 60 and standard...

2. A random sample of 25 male runners has a mean of ̄x= 60 and standard deviation s = 3 kilograms(kg). Suppose that the mean weights of male runners follow a normal distribution with unknown mean μ and unknown standard deviation σkg. Find a 90% confidence interval for μ. (10 pts.)

Homework Answers

Answer #1

Answer:

n= 25,   = 60 , s= 3

c= 90 %

formula for confidence interval is

Where tc is the t critical value for c= 90% with df=n-1 = 25-1 = 24

using t table we get critical value as

tc = 1.711

58.9734 <    < 61.0266

58.97 <    < 61.03

We get confidence interval as ( 58.97 , 61.03 )

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
2. A random sample of 25 male runners has a mean of ¯ x = 60...
2. A random sample of 25 male runners has a mean of ¯ x = 60 and standard deviation s = 3 kilograms (kg). Suppose that the mean weights of male runners follow a normal distribution with unknown mean µ and unknown standard deviation σ kg. Find a 90% confidence interval for µ. (10 pts.)
Suppose x has a mound-shaped distribution. A random sample of size 16 has sample mean 10...
Suppose x has a mound-shaped distribution. A random sample of size 16 has sample mean 10 and sample standard deviation 2. (b) Find a 90% confidence interval for μ (c) Interpretation Explain the meaning of the confidence interval you computed.
A random variable ?x has a Normal distribution with an unknown mean and a standard deviation...
A random variable ?x has a Normal distribution with an unknown mean and a standard deviation of 12. Suppose that we take a random sample of size ?=36n=36 and find a sample mean of ?¯=98x¯=98 . What is a 95% confidence interval for the mean of ?x ? (96.355,99.645)(96.355,99.645) (97.347,98.653)(97.347,98.653) (94.08,101.92)(94.08,101.92) (74.48,121.52)
Suppose a random sample of 12 male runners of college-age gave a mean weight of 151...
Suppose a random sample of 12 male runners of college-age gave a mean weight of 151 lbs with a standard deviation of 9 lbs. We would like to know whether or not the population from which this sample was selected has a lower mean weight than 160 lbs which is the mean weight of the population of college-aged males as a whole. The value of the t-statistic for testing the hypotheses of interest is t = -3.5. What is the...
X is a normal random variable with unknown mean μ and standard deviation σ = 5....
X is a normal random variable with unknown mean μ and standard deviation σ = 5. (a) Find the margin of error E in a 95 percent confidence interval for μ corresponding a random sample of size   (b) What size sample would be needed to have a margin of error equal to 1.5?
A random variable X is normally distributed. It has a mean of 254 and a standard...
A random variable X is normally distributed. It has a mean of 254 and a standard deviation of 21. List the givens with correct symbols: ? (σ N X̄ μ s X p n) = 254 ? (X̄ n σ s X p μ N) = 21 a) If you take a sample of size 21, can you say what the shape of the sampling distribution for the sample mean is?   ? Yes No Why or why not? Check all...
a.)A normal random variable X has unknown mean μ and standard deviation σ = 6. What...
a.)A normal random variable X has unknown mean μ and standard deviation σ = 6. What is the margin of error E for a 98 percent confidence interval for μ, based on a random sample of size b.)(b) What sample size would be needed in part (a) to have a margin of error
A sample of size = n 43 has sample mean = x 53.6 and sample standard...
A sample of size = n 43 has sample mean = x 53.6 and sample standard deviation = s 9.1 . Part: 0 / 2 0 of 2 Parts Complete Part 1 of 2 Construct a 90 % confidence interval for the population mean μ . Round the answers to one decimal place. A 90 % confidence interval for the population mean μ is
(1 pt) A random sample of 100 observations produced a mean of x-bar = 23.1 from...
(1 pt) A random sample of 100 observations produced a mean of x-bar = 23.1 from a population with a normal distribution and a standard deviation = 2.42. (a) Find a 90% confidence interval (b) Find a 99% confidence interval (c) Find a 95% confidence interval
A random sample of 40 child residents in a large population yielded a mean weight of...
A random sample of 40 child residents in a large population yielded a mean weight of x= 39.2 kilograms. Suppose it is known that the distribution of weight of child residents in this population has a standard deviation of 9.8 kilograms. A. Give an approximate 90% confidence interval for the mean weight of child residents in the population. B. What sample size is required if we want 90% confidence and the margin of error to be 1 kilogram?
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT