Question

The following table provides the starting players of a basketball team and their heights

Player | A | B | C | D | E |

Height (in.) | 75 | 77 | 79 | 82 | 87 |

a. The population mean height of the five players is _____ .

b. Find the sample means for samples of size 2.

A, B: x¯ = ___ .

A, C: x¯ = ___ .

A, D: x¯¯ = ___ .

A, E: x¯ = ____ .

B, C: x¯¯ = ____ .

B, D: x¯ = _____ .

B, E: x¯ = ____.

C, D: x¯ = ___ .

C, E: x¯ = ____ .

D, E: x¯ = ____ .

c. Find the mean of all sample means from above:

x¯ = ____ .

Answer #1

The population comprises of five basketball players A,B,C,D and E and their heights in inches are 75, 77, 79, 82 and 87.

a)

Thus, the population mean is (75 + 77 + 79 + 82 + 85) / 5 = 79.6

b)

We have 5 population units and we want to make samples of size 2 from them. Thus the total number of such samples is = 10.

The samples are (A, B) , (A, C) , (A, D) , (A, E) , (B, C) , (B, D) , (B, E) , (C, D) , (C, E) , (D, E).

The respective sample means are

A,B : ( 75 + 77)/2 = 76

A,C : (75 + 79)/2 = 77

A,D : (75 + 82)/2 = 78.5

A,E : (75 + 85)/2 = 80

B,C : (77 + 79)/2 = 78

B,D : (77 + 82)/2 = 79.5

B,E : (77 + 85)/2 = 81

C.D : (79 + 82)/2 = 80.5

C,E : (79 + 85)/2 = 82

D,E : (82 + 85)/2 = 83.5

c)

The means of the sample means are

(76 + 77 + 78.5 + 80 + 78 + 79.5 + 81 + 80.5 + 82 + 83.5)/10 = 79.6

The following table provides the starting players of a
basketball team and their heights
Player A B C D E Height (in.) 75 77 78 81 86
a. The population mean height of the five players is .
b. Find the sample means for samples of size 2.
A, B: ?¯ = .
A, C: ?¯ = .
A, D: ?¯ = .
A, E: ?¯ = .
B, C: ?¯ = .
B, D: ?¯ = .
B, E:...

Find the expected value and standard deviation of heights for a
basketball player on Team Z given the the following information.
hint: find the probability (relative frequency) for each height
first: Height (x in inches) # of Players 72 1 73 3 74 3 75 5 76 6
77 5 78 3 79 1 2. How would the expected value and standard
deviation change if the height for every player was was actually 1
inch taller? Provide both an explanation...

The heights of five starting players on a basketball team have a
mean of 76 inches, a median of 78 inches, and a range of 11
inches.
a. If the tallest of these five players is replaced by a
substitute who is 2inches taller, find the mean, median, and
range
b. If the tallest player is replaced by a substitute who is 4
inches shorter, which of the new values (mean, median, range) could
you determine and what would their...

The heights of basketball players have an approximate normal
distribution with mean, µ = 79 inches and a standard deviation, σ =
3.89 inches. For each of the following heights, calculate the
z-score and interpret it using complete sentences:
a) 74 inches
b) 87 inches
c) 77 inches
d) 60
inches
e) Explain, using statistical language, why the basketball
player’s recorded height in part d) above is likely an outlier.

The table on the right shows last initials of basketball players
and the number of games played by each. Find the z-score for
player F's
games played.
What is player F's
z-score?
Player
Games
Played
A
71
B
81
C
75
D
77
E
72
F
82
G
73
H
79
J
71
K
82

Soma recorded in the table the height of each player on the
basketball team
Basketball Players’ Heights (in inches)
66
66
68
57
64
65
67
67
64
65
Construct a normal probability distribution curve for this
population! Indicate the number for the mean, 1SD, 2SD
and 3SD (both sides of the mea) (1+ 6*0.5=4p)

The height of the five starting players of a Basket-Ball team
are(in inches)
68, 72, 75, 80, and 84.
a.) Find the population mean.
b.)Show that the mean of all the sample means of size 3 is
equal to the population mean.

The table on the right shows last initials of basketball players
and the number of games played by each. Find the z-score for
player
F's
games played.
Player
Games Played
A
73
B
79
C
71
D
81
E
76
F
78
G
75
H
79
J
74
K
82

Heights of a basketball team are known to not be normally
distributed. The team heights have a mean of 7.1ft and the standard
deviation 1.5 ft. a) Find the probability that 36 players have a
mean height between 6.2 ft and 7.5 ft. b) Explain why, for part a,
you were able to use the Central Limit Theorem to solve the
problem.

The following data values represent a sample of
the heights of female college basketball players. SHOW WORK.
Heights in Inches
65 66 66 67 68 68 68 69 69 69 69 70 71
72 72 72 73 75 75 75 75 76 76 76 76
a) Determine (to two decimal places) the mean height and sample
standard deviation of the heights.
b) Determine the z-score of the data value X = 75 to the
nearest hundredth.
c) Using results from...

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 5 minutes ago

asked 12 minutes ago

asked 22 minutes ago

asked 34 minutes ago

asked 45 minutes ago

asked 58 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago