Question

A] this problem requires PhStat solution. A marketing researcher wants to estimate the mean amount spent ($) on Amazon.com by Amazon Prime member shoppers. Suppose a random sample of 100 Amazon Prime member shoppers who recently made a purchase on Amazon.com yielded a mean amount spent of $1,500 and a standard deviation of $200. 1. Using a 0.05 level of significance, state your decision.

2. Using the critical value approach, is there evidence that the population mean amount spent on Amazon.com by Amazon Prime member shoppers is less than $1,475?

3. Determine the p-value and interpret its meaning.

B] **this problem requires PhStat solution.**

The population mean waiting time to check out of a supermarket has been 4 minutes. Recently, in an effort to reduce the waiting time, the supermarket has experimented with a system in which infrared cameras use body heat and in-store software to determine how many lines should be opened. A sample of 100 customers was selected, and their mean waiting time to check out was 4.25 minutes with a sample standard deviation of 2.7 minutes.

1. State your decision rule.

2. What is your decision?

3. At 0.05 level of significance, using the critical value approach, is there evidence that the population mean waiting time to check out is greater than 4 minutes?

4. Determine p-value and interpret its meaning.

LEGIBLY PLEASE THANK YOU ;-]

Answer #1

The population mean waiting time to check out of a supermarket
has historically been 4 minutes. In an effort to reduce the waiting
time, you, as store manager, conducted an experiment with infrared
cameras that use body heat and in-store software to determine how
many lanes should be opened. To test the effectiveness of this
process, you selected a random sample of 100 customers and recorded
their waiting time. For this sample, the mean waiting time to check
out was...

The population mean waiting time to check out of a supermarket
has historically been 4 minutes. In an effort to reduce the waiting
time, you, as store manager, conducted an experiment with infrared
cameras that use body heat and in-store software to determine how
many lanes should be opened. To test the effectiveness of this
process, you selected a random sample of 100 customers and recorded
their waiting time. For this sample, the mean waiting time to check
out was...

A marketing researcher wants to estimate the mean amount spent
($) on a certain retail website by members of the website's
premium program. A random sample of
95 members of the website's premium program who recently made a
purchase on the website yielded a mean of $2000 and a standard
deviation of $150.
Complete parts (a) and (b) below.
A ___ < U < ____
b. Interpret the interval constructed in (a).
Choose the correct answer below.
A.The sample mean...

A marketing manager needs to estimate the true mean dollar
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be adjusted to reflect a difference in mean spending from previous
amounts. She obtains the following sample statistics from a sample
of 100 Amazon Prime members who recently made a purchase: n 100 top
enclose y 1400 s 250 Using this information, she she can be 98%
confident...

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Q1-Suppose a wholesaler of paints wants to estimate the actual
amount of paint contained in 10 kg cans purchased from a paint
manufacturing company. It is known from the manufacturer's
specifications that the standard deviation of the amount of paint
is equal to 0.05 kg. A random
sample of 49 cans is selected yields an average amount of paint per
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Problem: The data set represents the amount of time (in minutes)
spent checking
email for a random sample of employees at a company.
7.5 2.0 12.1 8.8 9.4 7.3 1.9 2.8 7.0 7.3
1) Find the sample mean and the sample standard deviation.
2) Construct a 90% confidence interval for the population mean.
Interpret the results.
Assume the times are normally distributed.
3) Repeat part (2), assuming σ = 3.5 minutes. Compare the
results.

CCN and ActMedia provided a television channel targeted to
individuals waiting in supermarket checkout lines. The channel
showed news, short features, and advertisements. The length of the
program was based on the assumption that the population mean time a
shopper stands in a supermarket checkout line is 7.7 minutes. A
sample of actual waiting times will be used to test this assumption
and determine whether actual mean waiting time differs from this
standard.
a. Formulate the hypotheses for this
application....

The researcher recorded the amount of time each bird spent in
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produced a mean of M = 56.61 minutes on the plain chamber
with SS = 3752 for a sample of n = 14 birds.
Construct the 90% confidence interval to estimate the mean amount
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realized by shoppers who showroom. Showrooming is the practice of
inspecting products in retail stores and then purchasing the
products online at a lower price. A random sample of
100100
shoppers who recently purchased a consumer electronics item
online after making a visit to a retail store yielded a mean
savings of
$5555
and a standard deviation of
$5353.
The researcher believes the actual mean savings is
$4747.
Complete parts...

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