at a particular university, statistics students miss a mean of 2.1 days of school each semester with a standard deviation of 2.5 days. what is the probability that the mean number of days missed for a random sample of 64 students will be more than 3?
Solution :
Given that ,
mean = = 2.1
standard deviation = = 2.5
= / n = 2.5 / 64 = 0.3125
P( > 3) = 1 - P( < 3)
= 1 - P[( - ) / < (3 - 2.1) / 0.3125]
= 1 - P(z < 2.88)
= 1 - 0.998
= 0.002
Probability = 0.002
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