A poll reported that only 593 out of a total of 1594 adults in a particular region said they had a "great deal of confidence" or "quite a lot of confidence" in the public school system. This was down 5 percentage points from the previous year. Assume the conditions for using the CLT are met. Complete parts (a) through (d) below.
b. Find an 80% confidence interval and interpret it.
The 80% confidence interval for the proportion that express a great deal of confidence or quite a lot of confidence in the public schools is (__,__).
Round to three decimal places as needed.
We need to construct the 80% confidence interval for the population proportion. We have been provided with the following information about the number of favorable cases:
Favorable Cases X = | 593 |
Sample Size N = | 1594 |
The sample proportion is computed as follows, based on the sample size N = 1549 and the number of favorable cases X = 593
The critical value for α=0.2 is z_c = 1.282. The corresponding confidence interval is computed as shown below:
The 80% confidence interval for the proportion that express a great deal of confidence or quite a lot of confidence in the public schools is (0.357,0.388).
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