Return to Example 8.5: Serum cholesterol levels for all males 20 to 35 years old in the United States are approximately normally distributed with a mean of 186 mg/dL and standard deviation of 36 mg/dL.
solution
given that
P(150< x <258 ) = P[(150-186 ) / 36< (x - ) / < (258-186 ) /36 )]
= P( -1< Z <2 )
= P(Z <2 ) - P(Z <-1 )
Using z table
= 0.9772-0.1587
=0.8185
answer=81.9%
(B)
P( 186 < x <294 ) = P[( 186 -186 ) / 36< (x - ) / < (294 -186 ) /36 )]
= P(0< Z <3 )
= P(Z <3 ) - P(Z <0)
Using z table
= 0.9987-0.5
=0.4987
answer=49.9%
Get Answers For Free
Most questions answered within 1 hours.