In order to use a 90% confidence interval to compare admission exam scores for sophomores (group #1) and freshmen (group #2), two independent random samples were selected. The results showed:
1-Sophomores: Sample mean = 85, sample standard deviation = 10, sample size = 50.
2-Freshmen: Sample mean = 78, sample standard deviation = 12, sample size = 72.
For forming a 90% confidence interval for μ 1 − μ 2, the multiplier is __________ .
Group of answer choices
1.645
3
1.96
None of the other choices represent a suitable response.
2.576
According to this question, we are to find the 95% confidence interval for the null
Here we have,
Here,
Test-statistic will be-
qhich is distributed as t with degrees of freedom under null
i.e. ,the test is called Fisher's t-test.
The % confidence interval is then given by--
So, the multiplier is ,i.e. None of the choices represent a suitable response.,but 1.645 is approximately close to computed value of multiplier.
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