Question

Professor Jones took a random sample of 8 students and
asked them how many times per week they dine out. The responses
were:

2

2

3

4

5

5

77

88

Find the 95% confidence interval for the population mean.

Answer #1

A random sample of 13 students were asked how long it took them
to complete a certain exam. The mean length of time was 111.5
minutes, with a standard deviation of 83.0 minutes. Find the lower
bound of the 90% confidence interval for the true mean length of
time it would take for all students to complete the exam.

a random sample of 13 students were asked how long it took them
to complete a certain exam. The mean length of time was 122.1
minutes what the standard deviation of 66.6 minutes. Final lower
bound of 90% confidence interval for the true mean length of time
it would take for all students to complete the exam . Round to one
decimal place

A professor wants to estimate how many hours per week students
study. A simple random sample of 78 students had a mean of 15.0
hours of studying per week. Construct and interpret a 90%
confidence interval for the mean number of hours a student studies
per week. Assume the population standard deviation is known to be
2.3 hours per week

A random sample of 13 students were asked how long it took them
to complete a certain exam. The mean length of time was 117.6
minutes, with a standard deviation of 69.2 minutes. Find the lower
bound of the 90% confidence interval for the true mean length of
time it would take for all students to complete the exam. Round to
one decimal place (for example: 108.1). Write only a number as your
answer. Do not write any units.

A random sample of 13 students were asked how long it took them
to complete a certain exam. The mean length of time was 107.3
minutes, with a standard deviation of 82.5 minutes. Find the lower
bound of the 90% confidence interval for the true mean length of
time it would take for all students to complete the exam.
Round to one decimal place (for example: 108.1). Write only a
number as your answer. Do not write any units.

I asked a random sample of 15 adults, aged 25 - 50, how many
hours per week they spent playing video games. The responses were
as follows:
7, 15, 3, 1, 2, 2, 0, 0, 10, 5, 1, 1, 2, 0, 2
With a mean of 3.4 and a standard deviation of 4.256, determine
a 90% confidence interval.

Eating out. A survey asked 849 people how many
times per week they dine out at a restaurant. The results are
presented in the following table.
Number of Times
Frequency
0
116
1
232
2
246
3
146
4
54
5
23
6
26
7
6
Consider the 849 people to be a population. Let X be the number
of times per week a person dines out for a person sampled at random
from this population.
a.) compute the probability...

6) A random sample of high school girls were asked how many
hours per week they use social media. The sample mean of the 25
girls was 9 with standard deviation 2.7. What is the 90% confidence
interval for the true mean for the hours per week high school girls
use social media? Assume the population is normally
distributed.

A marketing professor asked a random sample of college students
who have cell phones how much their monthly bill was. He found the
sample mean was $100. Using a two-tailed significance test, he
rejected Ho: µ = $80 using the usual decision cutoff of α = 0.05.
Which one of the following could be a 95% confidence interval for
the mean monthly cell phone bill for all college students with cell
phones?
Show your reasoning.
a) ($70, $110)
b) ($70,...

A random sample of 90 UT business students revealed that on
average they spent 8 hours per week on Facebook. The population
standard deviation is assumed to be 2 hours per week.
If we want to develop a 95% confidence interval for the average
time spent per week on Facebook by all UT business students, the
margin of error of this interval is
The 95% confidence interval for the average time spent per week
on Facebook by all UT business...

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