Question

) In a room there are 28 men, of which 12 are republican and 16 are democrats. There are also

16 women of which 6 are republican and 10 are democrats.

a) What is the probability of randomly selecting a female democrat?

b) What is the probability of selecting a man or a democrat?

What is the probability of selecting a republican democrat?

d) What is the probability that the first person you select is a woman democrat and the

second person is a republican?

e) What is the probability that you have drawn a two or a red card if you are told that the

card in your hand is lower than a seven? (You are not including the seven)

Answer 1

	republican	Democrats	total
men	12	16	28
women	6	10	16
total	18	26	44

a)

probability of randomly selecting a female democrat =10/44=0.2273

b) probability of selecting a man or a democrat =(28+26-16)/44=0.8636

c) probability of selecting a republican democrat =0 (since either a person is republican or democrat

d)

probability that the first person you select is a woman democrat and the

second person is a republican =(10/44)*(18/43)=0.0951

e)since there are 6*4 =24 cards lower then seven if we consider ace as 1

and number of cards which are red or 2 and lower than 7 =6*2+2 =14

probability that you have drawn a two or a red card if you are told that the

card in your hand is lower than a seven =14/26 =7/13