Question

For the standard normal random variable *z*, compute the
following probabilities (if required, round your answers to four
decimal places):

*P*(0 ≤*z*≤ 0.77) =*P*(-1.63 ≤*z*≤ 0) =*P*(*z*> 0.42) =*P*(*z*≥ -0.22) =*P*(*z*< 1.30) =*P*(*z*≤ -0.78) =

Answer #1

Given that z is a standard normal random variable, compute the
following probabilities. (Round your answers to four decimal
places.)
(a)
P(z ≤ −3.0)
(b)
P(z ≥ −3)
(c)
P(z ≥ −1.3)
(d)
P(−2.4 ≤ z)
(e)
P(−1 < z ≤ 0)

Given that z is a standard normal random variable,
compute the following probabilities. (Round your answers to four
decimal places.)(a)P(0 ≤ z ≤ 0.86)(b)P(−1.54 ≤ z ≤ 0)(c)P(z > 0.44)(d)P(z ≥ −0.22)(e)P(z < 1.30)(f)P(z ≤ −0.75)Also..A population has a mean of 128 and a standard deviation of 32.
Suppose a sample of size 64 is selected andxis used to estimate μ. (Round your answers to four
decimal places.)(a)What is the probability that the sample mean will be within ±5
of...

Given that z is a standard normal random variable, compute the
following probabilities. Round your answers to 4 decimal
places.
a. P(0 _< z _< 0.51)
b. P( -1.61 _< z _< 0)
c. P( z > 0.30)
d. P( z _> -0.31)
e. P( z < 2.06)
f. P( z _< -0.61)

Find the following probabilities for the standard normal random
variable z. (Round your answers to four decimal places.)
(a) P(−1.43 < z < 0.64) =
(b) P(0.52 < z < 1.75) =
(c) P(−1.56 < z < −0.48) =
(d) P(z > 1.39) =
(e) P(z < −4.34) =

Find the following probabilities for the standard normal random
variable z. (Round your answers to four decimal
places.)
(a) P(?1.41 < z < 0.61) =
(b) P(0.55 < z < 1.78) =
(c) P(?1.54 < z < ?0.44) =
(d) P(z > 1.32) =
(e) P(z < ?4.31) =
You may need to use the appropriate appendix table or technology to
answer this question.

Let Z be a standard normal random variable and
calculate the following probabilities, drawing pictures wherever
appropriate. (Round your answers to four decimal places.)
a) P(0 <= Z <= 2.73)
b) P(Z <= 1.63)
c) P(-1.05 <= Z)
d) P(|Z| <= 2.5)
How do you do this or is there an easy way you can do this in
excel?

Let Z be a standard normal random variable and
calculate the following probabilities, drawing pictures wherever
appropriate. (Round your answers to four decimal
places.)
(e) P(Z ≤ 1.43)
(h) P(1.43 ≤ Z ≤
2.50)

Given that Z is a standard normal random variable, compute the
following probabilities (to 4 decimal places).
a. P(-1.98 ≤ z ≤ 0.49)
b. P(.55 ≤ z ≤ 1.28)
c. P(-1.79 ≤ z ≤ -1.09)

Let Z be a standard normal random variable and calculate the
following probabilities, drawing pictures wherever appropriate.
(Round your answers to four decimal places.)
(a) P(0 ≤ Z ≤ 2.57)
(b) P(0 ≤ Z ≤ 2)
(c) P(−2.80 ≤ Z ≤ 0)
(d) P(−2.80 ≤ Z ≤ 2.80)
(e) P(Z ≤ 1.14)
(f) P(−1.45 ≤ Z)
(g) P(−1.80 ≤ Z ≤ 2.00)
(h) P(1.14 ≤ Z ≤ 2.50)
(i) P(1.80 ≤ Z)
(j) P(|Z| ≤ 2.50)

Let Z be a standard normal random variable and calculate the
following probabilities, drawing pictures wherever appropriate.
(Round your answers to four decimal places.) (a) P(0 ≤ Z ≤ 2.42)
.4922 Correct: Your answer is correct. (b) P(0 ≤ Z ≤ 1) (c) P(−2.60
≤ Z ≤ 0) (d) P(−2.60 ≤ Z ≤ 2.60) .9953 Incorrect: Your answer is
incorrect. (e) P(Z ≤ 1.93) (f) P(−1.95 ≤ Z) (g) P(−1.60 ≤ Z ≤ 2.00)
(h) P(1.93 ≤ Z ≤ 2.50)...

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