Question

1. One-Way ANOVA

Case Processing Summary
	Cases
	Valid		Missing		Total
	N	Percent	N	Percent	N	Percent
Opinion * Community	96	100.0%	0	0.0%	96	100.0%

Opinion * Community Crosstabulation
			Community			Total
			A	B	C
Opinion	Against	Count	18	7	15	40
		Expected Count	17.5	9.2	13.3	40.0
	For	Count	12	6	5	23
		Expected Count	10.1	5.3	7.7	23.0
	NoOpinion	Count	12	9	12	33
		Expected Count	14.4	7.6	11.0	33.0
Total		Count	42	22	32	96
		Expected Count	42.0	22.0	32.0	96.0

Chi-Square Tests
	Value	df	Asymptotic Significance (2-sided)
Pearson Chi-Square	2.912a	4	.573
Likelihood Ratio	3.061	4	.548
N of Valid Cases	96
a. 0 cells (0.0%) have expected count less than 5. The minimum expected count is 5.27.

To include in your submission:

• Copy the ANOVA Table from the SPSS output to your Word document. Please make sure to adjust the size of your tables so that they fit on the page.
• Using the ANOVA table, answer the following for the one-way ANOVA:
  1. Type the hypotheses.
  2. Type in the test statistic found from the SPSS output.
  3. Type in the p-value found from the SPSS output.
  4. Type your decision regarding the null hypothesis.
  5. Type in your conclusion using context and units from the problem

Answer 1

NULL HYPOTHESIS H0: There is No association between opinion and community.

ALTERNATIVE HYPOTHESIS Ha: There is an association between opinion and community.

Test statisic= 2.912

P value= 0.573

Since P value is GREATER THAN THE LEVEL OF SIGNIFICANCE 0.05 therefore NOT SIGNIFICANT.

Decision: DO NOT REJECT NULL HYPOTHESIS H0.

CONCLUSION: We do not have sufficient evidence to conclude that there is an association between opinion and community at 0.05 level of Significance.