Suppose the purchases at a local convenience store are normally distributed with a mean of $10.50, and a standard deviation of $2.10.
If 7 customers are randomly selected, what is the probability that the mean purchase amount for these 7 customers is below $8.75?
Solution :
Given that ,
mean = = $10.50
standard deviation = = $2.10
= / n = 2.10 / 7 = 0.7937
P( < $8.75) = P(( - ) / < (8.75 - 10.50) / 0.7937)
= P(z < -2.2049)
= 0.0137
Probability = 0.0137
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