a)
here for uniform distribution parameter a =0 and b=12 |
pdf of X:
f(x)=1/(b-a) = | 1/12 for 0 <x<12 |
b)
c)
F(x) =x/12 where 0<X <12
d)
mean μ=(a+b)/2 = | 6 |
e)
standard deviation σ=(b-a)/√12= | 3.4641 |
f)
P(X<1)=(1-0)/12=0.0833 |
g)
P(4<X<5)=(5-4)/12=0.0833 |
h)
Find the probability that the commuter waits more than 3.6 minutes
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