Question

The life expectancy of a male during the course of the past 100 years is approximately...

The life expectancy of a male during the course of the past 100 years is approximately 27,789
days. Use the table to the right to conduct a test using alpha equals=0.05 to determine whether the evidence suggests that chief justices live longer than the general population of males. Suggest a reason why the conclusion drawn may be flawed.

Table:

Chief Justice Life Span (Days) Chief Justice Life Span (days)
A 27,280 I 32,407
B 29,301 J 26,836
C 30,057 K 32,964
D 28,206 L 32,719
E 32,954 M 29,707
F 30,024 N 28,819
G 31,299 O 31,804
H 32,292 P 27,089

-State the appropriate null and alternative hypotheses.

-Use the​ P-value approach at the alpha equals=0.05 level of significance to test the hypotheses.

P-Value:___

State the conclusion for the test. Choose the correct answer below.

A.Reject the null hypothesis. There is not sufficient evidence to conclude that the mean life span of males is longer than 27,789 days.​ Thus, there is not sufficient evidence to indicate that chief justices live longer than the general population of males.

B. Do not reject the null hypothesis. There is not sufficient evidence to conclude that the mean life span of males is longer than 27,789 days.​ Thus, there is not sufficient evidence to indicate that chief justices live longer than the general population of males.

C. Do not reject the null hypothesis. There is sufficient evidence to conclude that the mean life span of males is longer than 30,235 days.​ Thus, there is sufficient evidence to indicate that chief justices live longer than the general population of males.

D. Reject the null hypothesis. There is sufficient evidence to conclude that the mean life span of males is longer than 27,789 days.​ Thus, there is sufficient evidence to indicate that chief justices live longer than the general population of males.

-Suggest a reason why the conclusion drawn may be flawed. Choose the correct answer below.

A. The sample size is very large and the data are normally distributed.

B.The sample consists of outliers.

C.The sampled values are not independent of each other.

D.The sample is not obtained using simple random sampling or from a randomized experiment.

Homework Answers

Answer #1

from above p value =0.0002 ~0.000

D. Reject the null hypothesis. There is sufficient evidence to conclude that the mean life span of males is longer than 27,789 days.​ Thus, there is sufficient evidence to indicate that chief justices live longer than the general population of males.

2) D.The sample is not obtained using simple random sampling or from a randomized experiment.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
From a random sample from normal population, we observed sample mean=84.5 and sample standard deviation=11.2, n...
From a random sample from normal population, we observed sample mean=84.5 and sample standard deviation=11.2, n = 16, H0: μ = 80, Ha: μ < 80. State your conclusion about H0 at significance level 0.01. Question 2 options: Test statistic: t = 1.61. P-value = 0.9356. Reject the null hypothesis. There is sufficient evidence to conclude that the mean is less than 80. The evidence against the null hypothesis is very strong. Test statistic: t = 1.61. P-value = 0.0644....
Exhibit 10-1 Salary information regarding two independent random samples of male and female employees of a...
Exhibit 10-1 Salary information regarding two independent random samples of male and female employees of a large company is shown below. Male Female Sample size 64 36 Sample mean salary (in $1000s) 44 41 Population variance 128 72 Refer to Exhibit 10-1. At 95% confidence, we have enough evidence to conclude that the  _____. a. We fail to reject the null hypothesis; we conclude that the average average salary of males is at least as much as females. b. We reject...
Lifespan: Assume the average life-span of those born in the U.S. is 78.2 years with a...
Lifespan: Assume the average life-span of those born in the U.S. is 78.2 years with a standard deviation of 16 years. The distribution is not normal (it is skewed left). The good people at Live-Longer-USA (fictitious) claim that their regiment of acorns and exercise results in longer life. So far, 35 people on this program have died and the mean age-of-death was 83.5 years. (a) Calculate the probability that a random sample of 35 people from the general population would...
Assume the average life-span of those born in the U.S. is 78.2 years with a standard...
Assume the average life-span of those born in the U.S. is 78.2 years with a standard deviation of 16 years. The distribution is not normal (it is skewed left). The good people at Live-Longer-USA (fictitious) claim that their regiment of acorns and exercise results in longer life. So far, 40 people on this program have died and the mean age-of-death was 84.9 years. (a) Calculate the probability that a random sample of 40 people from the general population would have...
Lifespan: Assume the average life-span of those born in the U.S. is 78.2 years with a...
Lifespan: Assume the average life-span of those born in the U.S. is 78.2 years with a standard deviation of 16 years. The distribution is not normal (it is skewed left). The good people at Live-Longer-USA (fictitious) claim that their regiment of acorns and exercise results in longer life. So far, 35 people on this program have died and the mean age-of-death was 82.9 years. (a) Calculate the probability that a random sample of 35 people from the general population would...
Lifespan: Assume the average life-span of those born in the U.S. is 78.2 years with a...
Lifespan: Assume the average life-span of those born in the U.S. is 78.2 years with a standard deviation of 16 years. The distribution is not normal (it is skewed left). The good people at Live-Longer-USA (fictitious) claim that their regiment of acorns and exercise results in longer life. So far, 50 people on this program have died and the mean age-of-death was 85.5 years. (a) Calculate the probability that a random sample of 50 people from the general population would...
A shareholders' group is lodging a protest against your company. The shareholders group claimed that the...
A shareholders' group is lodging a protest against your company. The shareholders group claimed that the mean tenure for a chief exective office (CEO) was at least 11 years. A survey of 109 companies reported in The Wall Street Journal found a sample mean tenure of 10.6 years for CEOs with a standard deviation of 4.1 years (The Wall Street Journal, January 2, 2007). You want to formulate and test a hypothesis that can be used to challenge the validity...
You wish to test the claim that the average IQ score is less than 100 at...
You wish to test the claim that the average IQ score is less than 100 at the .005 significance level. You determine the hypotheses are: Ho: μ=100 H1:μ<100 You take a simple random sample of 76 individuals and find the mean IQ score is 95.5, with a standard deviation of 15.1. Let's consider testing this hypothesis two ways: once with assuming the population standard deviation is not known and once with assuming that it is known. Round to three decimal...
You wish to test the claim that the average IQ score is less than 100 at...
You wish to test the claim that the average IQ score is less than 100 at the .01 significance level. You determine the hypotheses are: H o : μ = 100 H 1 : μ < 100 You take a simple random sample of 60 individuals and find the mean IQ score is 98.7, with a standard deviation of 14.6. Let's consider testing this hypothesis two ways: once with assuming the population standard deviation is not known and once with...
You wish to test the claim that the average IQ score is less than 100 at...
You wish to test the claim that the average IQ score is less than 100 at the .005 significance level. You determine the hypotheses are: H o : μ = 100 H 1 : μ < 100 You take a simple random sample of 95 individuals and find the mean IQ score is 95.2, with a standard deviation of 14.4. Let's consider testing this hypothesis two ways: once with assuming the population standard deviation is not known and once with...