It is given that 11 out of 200 flights are with late departures.
Then in order to find the 95% confidence interval we will use binomial proportion
here x = 11
n = 200
So 95% CI is given by:
where
and
is the critical value of standard normal distribution.
substituting values in the above equation we get CI
which suggests that if we draw 100 samples then 95 samples out of them have proportion between above given interval.
i.e., is the 95% confident that proportion of late departures lies in this interval.
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