Question

Using the 95% CI given on the prior problem (repeated here); Variable n Sample Mean Std....

Using the 95% CI given on the prior problem (repeated here);

Variable

n

Sample Mean

Std. Err.

L. Limit

U. Limit

pH_level

90

4.577889

not given

4.5181427

4.6376348

What are the upper and lower bounds if we had constructed a 90% confidence interval, using the same sample data?

a.

(4.518 ; 4.638)

b.

(4.528 ; 4.628)

c.

(4.559 ; 5.717)

d.

(4.507 ; 4.649)

e.

(4.757 ; 4.899)

Homework Answers

Answer #1

95% confidence limit = ( 4.5181427, 4.6376348 )

Sample mean = 4.577889

We need to construct the limit for 90% confidence interval

Now, obtain margin of error

margin of error = Upper limit - mean = 4.6376348 - 4.577889

margin of error = 0.0597458

z_c for 90% CI = 1.645

z_c for 95% CI = 1.96

This is the only difference in margin of error

New margin of error = ( margin of error /1.645)*1.96

New margin of error = (   0.0597458 / 1.645 )*1.96

New margin of error = 0.0711864

95% confidence interval = ( mean - new margin of error , mean + new margin of error )

95% confidence interval = ( 4.577889 - 0.0711864, 4.577889 + 0.0711864 )

95% confidence interval = ( 4.507, 4.649 )

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