The Wilson family was one of the first to come to the U.S. They
had 5 children. Assuming that the probability of a child being a
girl is .5, find the probability that the Wilson family had:
at least 3 girls?
at most 3 girls?
Here, n = 5, p = 0.5, (1 - p) = 0.5 and x = 3
As per binomial distribution formula P(X = x) = nCx * p^x * (1 -
p)^(n - x)
We need to calculate P(X >= 3).
P(X >= 3) = (5C3 * 0.5^3 * 0.5^2) + (5C4 * 0.5^4 * 0.5^1) + (5C5
* 0.5^5 * 0.5^0)
P(X >= 3) = 0.3125 + 0.1563 + 0.0313
P(X >= 3) = 0.5001
Here, n = 5, p = 0.5, (1 - p) = 0.5 and x = 3
As per binomial distribution formula P(X = x) = nCx * p^x * (1 -
p)^(n - x)
We need to calculate P(X <= 3).
P(X <= 3) = (5C0 * 0.5^0 * 0.5^5) + (5C1 * 0.5^1 * 0.5^4) + (5C2
* 0.5^2 * 0.5^3) + (5C3 * 0.5^3 * 0.5^2)
P(X <= 3) = 0.0313 + 0.1563 + 0.3125 + 0.3125
P(X <= 3) = 0.8126
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