aspect | diameter |
north | 27.8 |
north | 14.5 |
north | 39.1 |
north | 3.2 |
north | 58.8 |
north | 55.5 |
north | 25 |
north | 5.4 |
north | 19 |
north | 30.6 |
north | 15.1 |
north | 3.6 |
north | 28.4 |
north | 15 |
north | 2.2 |
north | 14.2 |
north | 44.2 |
north | 25.7 |
north | 11.2 |
north | 46.8 |
north | 36.9 |
north | 54.1 |
north | 10.2 |
north | 2.5 |
north | 13.8 |
north | 43.5 |
north | 13.8 |
north | 39.7 |
north | 6.4 |
north | 4.8 |
south | 44.4 |
south | 26.1 |
south | 50.4 |
south | 23.3 |
south | 39.5 |
south | 51 |
south | 48.1 |
south | 47.2 |
south | 40.3 |
south | 37.4 |
south | 36.8 |
south | 21.7 |
south | 35.7 |
south | 32 |
south | 40.4 |
south | 12.8 |
south | 5.6 |
south | 44.3 |
south | 52.9 |
south | 38 |
south | 2.6 |
south | 44.6 |
south | 45.5 |
south | 29.1 |
south | 18.7 |
south | 7 |
south | 43.8 |
south | 28.3 |
south | 36.9 |
south | 51.6 |
1. Consider the variable diameter.
a. Identify what the variable type of diameter is. Be as specific as possible.
b. Identify the level of measurement of diameter.
c. Identify the name(s) of appropriate graph(s) for diameter that you learned to produce in R in Lab 2.
d. Identify all measures of center that can be applied to diameter. Then find the values
of those measures.
a. Diameter is a continuous numeric type. It is an integer variable.
b. Level of measurement of diameter is Ratio scale
c. For diameter, box plot and histogram can be plotted
d. Measure of center for diameter will be mean, median and mode.
Mean is the of sum of all values divided by the number of available values.
Mean = 29.1167
Median is the mid-value
Median = (N/2)th item
Here, N = 60. Hence, Median is 60/2 = 30th item
Arrange the given data in ascending order and find the 30th item. 29.1 is the 30th item. Hence, Median = 29.1
Mode is the most occurring value
There are two values which repeats twice 13.8 and 36.90. There are 2 modes in this data
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