Question

question25

Assume that the probability of a being born with Genetic Condition B is p=p=7/20. A study looks at a random sample of 875 volunteers.

Find the most likely number of the 875 volunteers to have Genetic Condition B.
(Round answer to one decimal place.)
μ =

Let XX represent the number of volunteers (out of 875) who have Genetic Condition B. Find the standard deviation for the probability distribution of XX.
(Round answer to two decimal places.)
σ =

Use the range rule of thumb to find the minimum usual value μ–2σ and the maximum usual value μ+2σ.
Enter answer as an interval using square-brackets only with whole numbers.
usual values =

Answer 1

p= 7/20 = 0.35

n = 875

formula for Mean ( μ ) is

μ = n * p

μ = 875 * 0.35

μ = 306.25

round answer to one decimal place.

μ = 306.3

formula for standard deviation is

σ = 14.10895

round answer to two decimal places.

σ = 14.11

using range rule of thumb to find the minimum usual value μ–2σ and the maximum usual value μ+2σ

μ–2σ =  306.3 - ( 2 * 14.11 ) = 278.08

μ+2σ =  306.3 + ( 2 * 14.11 ) = 334.52

round to whole number

usual values = [ 278  ,  335 ]