Question

Assume that trees are subjected to different levels of carbon dioxide atmosphere with 7% of the trees in a minimal growth condition at 340 parts per million (ppm), 12% at 460 ppm (slow growth), 46% at 530 ppm (moderate growth), and 35% at 630 ppm (rapid growth). What is the mean and standard deviation of the carbon dioxide atmosphere (in ppm) for these trees? The mean is ppm. [Round your answer to one decimal place (e.g. 98.7).] The standard deviation is ppm. [Round your answer to two decimal places

Answer 1

Here, we have given that

Xi: carbon dioxide minimal growth condition at parts per million (ppm)

Xi

340

460

530

630

n= number of observations=4

Now, we want to find the mean and standard deviation

=Sample Mean =  

and

S=Sample standard deviation =

=

=121.93

we get the mean = 490.0 ppm

and Sample standard deviation = 121.93 ppm