The mean starting salary for nurses is $67,694 nationally. The standard deviation is approximately $11,333. The starting salary is normally distributed. A sample 35 starting salaries for nurses is taken. Find the probability that the sample mean is more than $68,000. Represent the probability with a graph.
.Solution :
_{} = / n = 11333 / 35
P( > 68000) = 1 - P( < 68000)
= 1 - P[( - _{} ) / _{} < (68000 - 67694) / 11333 / 35 ]
= 1 - P(z < 0.16)
= 0.4365
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