Here' the answer to the question. please write back in
case you've doubts.
20)
P(both ace) = ?
Remember this is draws with replacement, so events are independent.
Also, there are 4 Aces in a pack of 52 cards, so P(get a Ace on a draw) = 4/52
So, P(getting ace both times) = (4/52)*(4/52) = 0.0059
21)
Again, rolling a die is indepenent of tossing a coin.
So, given that the coin rolled tails ( which happens with .5 probability), the chances of getting 5 is ?
P(getting any number on a fair dice) = 1/6 , as there are 6 numbers on a dice with each number getting a 1/6 probability to show up.
P(getting a 5 on the die given the coin landed tails up)
= P(coin gives tail)*P(get 5 on dice)/P(coin gives tail)
= (1/2)*(1/6)/ ( 1/2)
= 1/6
Get Answers For Free
Most questions answered within 1 hours.