Assume that 75% of the U.S. driving population have been ticketed for at least one speeding violation. If you choose 200 people to sample, what is the probability that less than 80% of these people have a speeding ticket on their driving record?
Solution
= [p ( 1 - p ) / n] = [(0.75 * 0.25) / 200 ] = 0.03062
P( < 0.80) =
= P[( - ) / < (0.80 - 0.75) / 0.03062]
= P(z < 1.63)
= 0.9484
Probability = 0.9484
=
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